Sunday, September 7, 2014

Solving 2 Step Algebraic Equations

Introduction

In our previous lesson, we covered solving 1 step algebraic equations. Well, in this lesson, we will be covering the same concept except we will be dealing with 2 step equations. Let's take a look at an example!

Solving 2 Step Equations

Let's say that we have the following equation:

2y + 3 = 15

In order to solve any 2 step equation, you will always do addition/subtraction first. Then you will do multiplication/division.

So, first we will subtract 3 since we have +3 is our equation:
2y + 3 = 15
      - 3 = - 3
2y = 12

Now, we will divide by 2 because we have 2 times y in our equation:
2y + 3 = 15
      - 3 = - 3
      2y = 12
       2  =  2
        y =  6

Checking your Answer!

To make sure that your answer is correct, you can always replace the variable with the answer then solve to get the answer!

2y + 3 = 15
y = 6
2 x 6 + 3 = 15
12 + 3 = 15
15 = 15



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