Perimeter Word Problem Involving Variables - Algebra I

In this video, you will learn how to solve perimeter word problems involving variables. For example, if you have a rectangle, the formula for perimeter is 2L + 2W. Based on the measurements given, you will substitute into the formula to find the length and width.

Perimeter Word Problem Involving Variables - Algebra I

How to Convert Standard Form to Slope Intercept Form - Algebra I

In this video, you will learn how to rewrite an equation from standard form to slope intercept form. Standard form is ax+by=c in which a and b are coefficients and c is a constant. Slope intercept form is y=mx+b, in which m is the slope and b is the y-intercept. In order to rewrite an equation from standard form to slope intercept form, you have to solve for the value of y. Then, rewrite to have the equation in slope intercept form.

How to Convert Standard Form to Slope Intercept Form - Algebra I

Introduction to Consecutive Integers - Algebra I

In this video, we will be doing an introduction to consecutive integers. Consecutive integers are integers that follow each other in a specified patterned order. This video will cover the basics of algebra I consecutive integers with four detailed step-by-step examples. Thanks for watching, and subscribe for much more!

Introduction to Consecutive Integers - Algebra I

Consecutive Integers and Word Problems (Sum of Consecutive Integers) - Algebra I

In this video, you will learn how to find a pair of consecutive integers by using word problems. Consecutive integers are integers that follow each other in a patterned order. For each word problem, you will set up the problem based on how many integers you are looking for. The first integer will always be a variable, the others following in a specified patterned order. To learn more, watch the video, hit like, and subscribe for more!

Consecutive Integers and Word Problems (Sum of Consecutive Integers) - Algebra I

Quadratic Formula and the Discriminant - Algebra I

In this video, you will learn about the quadratic formula and the discriminant. The discriminant is the value that determines how many solutions and the type of solutions that a quadratic equation has. The quadratic formula is a method for solving a quadratic equation. In the quadratic formula, there is a part under the radical, which is b^2-4ac. This part of the formula is what's used to find the value of the discriminant. The first step is to put your quadratic equation into ax^2+bx+c form. Next, you identify the values of a, b, and c. Now you will substitute these values into b^2-4ac to find the discriminant. If the value is positive, there are 2 real solutions. If the value is negative, then there are 2 complex solutions. If the value is equal to 0, then there is one real solution.

Quadratic Formula and the Discriminant - Algebra I

Solving Quadratic Equations using Factoring - Algebra I

In this video, you will learn how to solve a quadratic equation using factoring. A quadratic equation is always in the form of ax^2+bx+c. The x^2 term is what makes an equation quadratic. There are several methods to solve a quadratic equation, one of which is called factoring. When factoring to solve a quadratic equation, you first put the equation into ax^2+bx+c form, and then factor to get two binomials. Set each binomial equal to zero, and the numbers you get as a result of solving, will be your solutions to the quadratic equation.

Solving Quadratic Equations using Factoring - Algebra I

Solving Systems of Linear Inequalities - Algebra I

In this video, you will learn how to solve a system of linear inequalities. Linear inequalities have the symbols of greater than, less than, greater than or equal to, and less than or equal to. When you are solving a system of linear inequalities, you solving for the variables. Since these are inequalities, you won't get an exact answer, but you get a range of the solutions. Once you have gotten that, you will shade based upon the symbol in the inequality. The shaded part that overlaps both lines in the solution of the inequality. Any point within that shaded area will make the inequalities true.

Solving Systems of Linear Inequalities - Algebra I

Compound Inequalities - Algebra I

In this video, you will learn how to solve compound inequalities. An inequality is determined by the symbols greater than, less than, greater than or equal to, and less than or equal to. A compound inequality can be an 'and' compound inequality, or an 'or' compound inequality. In an 'and' compound inequality, the two point son the number line, which represent the solutions to each of the inequalities, are shaded so that the solution of the entire compound inequality is within both points. To solve for the solution, you simply use inverse operations. Solving an inequality is similar to solving an equation, except you don't get an exact solution. To learn more, watch the following video for step by step instructions.

How to Solve Compound Inequalities - Algebra I

Using Graphs to Relate Two Quantities - Algebra I

In this video you will learn how to use graphs to relate two quantities. Two important key words that you need to know for this topic are independent variable and dependent variable. Independent variable is the input value of a function and is always graphed on the x-axis. The dependent variable is always graphed on the y-axis and is the output value of a function. The example provided in this video is a word problem in which you have to identify the independent and dependent variable. Then you have to describe how to graph relates to both quantities. For more details on this topic, please watch the following algebra video.

Using Graphs to Related Two Quantities - Algebra 1

Solving Inequalities with Addition or Subtraction - Algebra I

In this video you will learn how to solve inequalities with addition or subtraction. To solve with addition or subtraction means that in order to find the solution of the inequality you only have to add or subtract. Inverse operations are the opposite operations which help to find the solution. Since the inverse of addition is subtractions, that means the inverse of subtraction is addition! Therefore, just these two operations can solve an inequality in this topic.

How to Solve Inequalities with Addition or Subtractions Operations - Algebra 1

How to Solve Equations with Variables on Both Sides - Algebra I

In this video you will learn how to solve an equation with variables on both sides. The first step is to combine like terms. Then use inverse operations to eliminate the values that are being added, subtracted, etc. to the variable. Inverse operations are opposite operations. The inverse of addition is subtraction and the inverse of multiplication is division. Equations with variables on both sides often have the same variable which you have to find the value of. Otherwise, if there are two different variables, solve for the given variable.

How to Solve Equations with Variables on Both Sides - Algebra 1

Simplify Expressions using Distributive Property - Algebra I

In this video you will learn how to simplify an expression using the distributive property. An expression in a mathematical phrase which includes variables, operators, and numbers. In the Distributive Property, you distribute a single outer term to two or more terms within the parenthesis. This math tutorial will show you several examples of expressions and how to simplify them using the Distributive Property.

How to Simplify Expressions by using Distributive Property - Algebra 1